Matches 1 to 5 of 5 for Last Name equals BRINGOLD AND Tree equals Kinchen Hays
# | Last Name, Given Name(s) | Person ID | Born/Christened | Location |
---|---|---|---|---|
1 |
BRINGOLD Steffan (1536) | I12020 | b. Abt 1536 | St. Steffan, Bern, Switzerland |
2 |
BRINGOLD Peter (1619) | I12016 | b. 19 Sep 1619 | St. Steffan, Bern, Switzerland |
3 |
BRINGOLD Christen (1669) | I12014 | b. 04 Apr 1669 | St. Steffan, Bern, Switzerland |
4 |
BRINGOLD Christen (1577) | I12018 | b. Abt 1577 | St. Steffan, Bern, Switzerland |
5 |
BRINGOLD Benedicta (1734) | I12004 | b. 1734 | Lenk Im Simmental, Bern, Switzerland |